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Text File  |  1993-12-11  |  2KB  |  21 lines

  1. "AST1CAL3 EQUATION VARIABLE","12-11-1993","13:02:36"
  2. "PRESSURE=P+UIF(P)*R*G/NZE(MW)*T/NZE(V) VOLUME=V+UIF(V)*R*G/NZE(MW)*T/NZE(P) GRAMS=G+UIF(G)*P*V*MW/NZE(R*T) MOLEWEIGHT=MW+UIF(MW)*R*G/NZE(P*V)*T TEMP[K]=T+UIF(T)*P*V*MW/NZE(R*G) MOLES=GRAMS/NZE(MOLEWEIGH) DENSITY=GRAMS/NZE(VOLUME)"
  3. "IDEAL GAS, PRESSURE, VOLUME, TEMPERATURE, MOLES, GRAMS,        MOLECULAR WEIGHT, DENSITY.                                                                                                                                      Ideal gases follow the behavior expressed in the ideal gas law:                                                                                                             P * V = N * R * T    gas constant R=0.0821 atm∙L/(mole ∙ K)                                                       R=8.31 J/(mole ∙ K)               where P is pressure in Pascals/atm, V is volume in liters, N is moles and       T is temperature in Kelvin (°C +273). Further, N = grams/(molecular weight) and density = grams/volume.  Select R for either Pascals or atm.  Enter any 4 of theremaining 5 variables as nonzero.  The unknown is entered as 0. Program will    calculate all 5 variables, moles and density.                                                                                                                                                                   (c) Copyright PCSCC, Inc., 1993 *** Answer(s) to problem ***                                                    Set G=3, MW=0, P=0, R=0.0821, T=273 and V=5.5.   Move cursor to MW and type S.  Use the default variable PRESSURE, type (enter).  For its value, type (end esc) 0.2654 (enter).  Use the default search range and type (enter).  The molecular  weight is 46.06 g which is that of ethanol.           Type any key to exit.                    || 3 grams of an unknown gas exert a pressure of 0.2654 atm at   T=273 K in a 5.5 liter gas cell. (a) What is the molecular weight of the gas?        Type comma key to see answer.  Type (F2) to return to application file."
  4. 13
  5. .2653999999999999,0,""
  6. 5.5,0,""
  7. 3,0,""
  8. 46.06419127217923,0,""
  9. 273,0,""
  10. 6.512650970629043D-02,0,""
  11. .5454545454545455,0,""
  12. 0,0,""
  13. 46.06419127217923,0,""
  14. 5.5,0,""
  15. .0821,0,""
  16. 3,0,""
  17. 273,0,""
  18. 1
  19. 0
  20. 0
  21.